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Section - B

Question - 3

Define a class called with the following specifications:

Class name: Eshop

Member variables:

String name: name of the item purchased

double price: Price of the item purchased

Member methods:

void accept(): Accept the name and the price of the item using the methods of Scanner class.

void calculate(): To calculate the net amount to be paid by a customer, based on the following criteria:

Price	Discount
1000 - 25000	5.0%
25001 - 57000	7.5%
57001 - 100000	10.0%
More than 100000	15.0%

void display(): To display the name of the item and the net amount to be paid.

Write the main method to create an object and call the above methods.

Answer

import java.util.Scanner;
class Eshop {
    String name;
    double price;
    void accept() {
        Scanner sc = new Scanner(System.in);
        name = sc.nextLine();
        price = sc.nextDouble();
    }
    double calculate() {
        double discount = 0.0;
        if (price > 100000) {
            discount = 15.0;
        } else if (price > 57000) {
            discount = 10.0;
        } else if (price > 25000) {
            discount = 7.5;
        } else if (price > 1000) {
            discount = 5.0;
        }
        return ((100.0 - discount) / 100.0) * price;
    }
    void display() {
        System.out.println("Name of item: " + name + "\nNet amount to be paid: Rs. " + calculate());
    }
    public static void main(String[] args) {
        Item item = new Item();
        item.accept();
        item.display();
    }
}

Question - 4

Define a class to accept values in integer array of size 10. Sort them in an ascending order using selection sort technique. Display the sorted array.

import java.util.Scanner;

public class ArraySort {
    public static void main(String args[]) {
        int[] nums = new int[10];

        // Input
        Scanner sc = new Scanner(System.in);
        for (int i = 0; i < 10; i++) {
            nums[i] = sc.nextInt();
        }

        // Sort
        for (int step = 0; step < size - 1; step++) {
            int min_idx = step;

            for (int i = step + 1; i < size; i++) {

                if (array[i] < array[min_idx]) {
                    min_idx = i;
                }
            }

            int temp = array[step];
            array[step] = array[min_idx];
            array[min_idx] = temp;
      }

      // Display
      for (int i = 0; i < 9; i++) {
        System.out.print(nums[i] + ", ");
      }
      System.out.println(nums[9]);
    }
}

Question - 5

Define a class to accept a string and convert it into uppercase. Count and display the number of vowels in it.

Input: robotics

Output: ROBOTICS

Number of vowels: 3

Answer

import java.util.Scanner;
class UpperCaseVowel {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String input = sc.nextLine();
        System.out.println("Upper Case: " + input.toUpperCase());
        int count = 0;
        for (int i = 0; i < input.length(); i++) {
            switch (input.charAt(i)) {
                case 'a':
                case 'e':
                case 'i':
                case 'o':
                case 'u':
                    count++;
                    break;
            }
        }
        System.out.println("Number of Vowels: " + count);
    }
}

Question - 6

Define a class to accept values into a 3×3 array and check if it is a special array. An array is a special array if the sum of the even elements = sum of the odd elements.

Example:

A[][]={{ 4 ,5, 6}, { 5 ,3, 2}, { 4, 2, 5}};
Sum of even elements = 4+6+2+4+2 =18
Sum of odd elements= 5+5+3+5=18

Answer

import java.util.Scanner;
class SpecialArray {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int[][] array = int[3][3];
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                System.out.print("Value for item in row " + j + " and column " + i + " > ");
                array[i][j] = sc.nextInt();
            }
        }
        int evenSum = 0, oddSum = 0;
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                if (array[i][j] % 2 == 0) {
                    evenSum += array[i][j];
                } else {
                    oddSum += array[i][j];
                }
            }
        }
        System.out.println("is special array? " + (oddSUm == evenSum));
    }
}

Question - 7

Define a class to accept a 3 digit number and check whether it is a duck number or not. Note: A number is a duck number if it has zero in it.

Example1:
    Input: 2083
    Output: Invalid
Example 2:
    Input: 103
    Output: Duck number

Answer

import java.util.Scanner;
class  {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int num = sc.nextInt();
        if (num >= 100 && num <= 999) {
            do {
                if (n % 10 == 0) {
                    System.out.println("Duck Number");
                    return; // stop function execution.
                }

                n = n / 10;
            } while (n > 0);
        }
        System.out.println("Invalid")
    }
}

Question - 8

Define a class to overload the method display as follows:

void display(): To print the following format using nested loop
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5

void display(int n): To print the square root of each digit of the given number
Example: n = 4329
output –    3.0
            1.414213562
            1.732050808
            2.0

Answer

class TriangleAndSqrts {
    void display() {
        for (int i = 0; i < 5; i++) {
            for (int j = 1; j <= i + 1; j++) {
                System.out.print(j + " ");
            }
            System.out.println();
        }
    }
    void display(int n) {
         do {
            System.out.println(Math.sqrt(n % 10));
            n = n / 10;
        } while (n > 0);
    }
}